Jrue Holiday signs four-year, $160m contract extension with Bucks

New York, April 5: Milwaukee Bucks star Jrue Holiday has signed a lucrative four-year contract extension worth up to $160million with the NBA franchise.

The Bucks confirmed the deal on Sunday (April 4), with All-Star Holiday declining his player option for the 2021-22 season as part of the agreement.

Holiday’s agent Jason Glushon told ESPN that the deal includes a player option for the fourth year in 2024-25 as the Bucks – chasing their first championship since 1971 – solidify their core of two-time reigning MVP Giannis Antetokounmpo, Khris Middleton and the former.

The Bucks acquired guard Holiday from the New Orleans Pelicans via a four-team trade in November.

“I’m a Buck for life,” Holiday said in a video via Milwaukee’s Twitter account. “Just know that I’m glad to be a part of Bucks Nation.

Let’s do some big things, man. I’m really excited.” Holiday is averaging 17.0 points, 5.4 assists, 4.6 rebounds and 1.82 steals (second in the NBA) in 31.7 minutes per game this season.

In Holiday’s 35 starts, the Bucks have tallied a 25-10 record. He is shooting a career-high 50.9 per cent from the field to go with 39.0 per cent from three-point range.

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